HomeQuizNEET MCQ on Hardy Weinberg Law
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1. In the Caucasian population of the US, 1 in 2500 babies is affected by a recessive condition – cystic fibrosis In this population, the frequency of the dominant allele is

2. A sampled “a” population has 36% of homozygous recessive genotype (aa) Then the frequency of allele “a” is

3. 360 out of 1000 individuals in a population have a genotype of AA while 480 have Aa genotype The rest 160 belong to aa Frequency of allele A in this population is

4. A gene locus has two alleles A and a If the frequency of dominant allele A is 4, then the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population is

5. What does p

6. 25 individuals in a population are homozygous dominant, then the individuals that are expected to be homozygous recessive are

7. Consider a population of sheep to be in Hardy-Weinberg equilibrium The allele for black wool(w) has an allele frequency of 81 while the allele for white wool(W) has an allele frequency of Then the percentage of heterozygous individuals in the population is

8. This condition is essential for a population to be in the Hardy-Weinberg equilibrium

9. This statement describes the Hardy-Weinberg law the best

10. This is true of the population which are included in Hardy-Weinberg equilibrium

11. Hardy-Weinberg equilibrium operates in the absence of