1. In the given figure, ΔACB ~ ΔAPQ. If AB = 6 cm, BC = 8 cm, and PQ = 4 cm then AQ is equal to

2. ΔDEF ~ ΔABC. If DE : AB = 2 : 3 and ar ΔDEF is equal to 44 square units then ar (ΔABC) (square unit) is

3. ΔABC and ΔBDE are two equilateral triangles such that D is the mid point of BC. Ratio of the areas of triangle ΔABC and ΔBDE is.

4. If ΔABC ~ ΔPQR, \(\frac{ar ΔABC}{ar ΔPQR}\) = \(frac{9}{4}\) and AB = 18 cm, then the length of PQ is

5. In the given figure ΔABC ~ ΔPQR, PM is median of ΔPQR. If ar ΔABC = 289 cm², BC = 17 cm, MR = 6.5 cm then the area of ΔPQM is

6. If the ratio of the perimeters of two similar triangles is 4 : 25, then the ratio of the areas of the similar triangles is

7. In the given figure, PQ = 24 cm, QR = 26 cm ∠PAR = 90°, PA = 6 cm, and AR = 8 cm, the degree measure of ∠QPR is

8. In the given figure the value of x is

9. ΔPQR is an equilateral triangle with each side of length 2p. If PS ⊥ QR, then PS is equal to

10. In ΔLMN, ∠L = 50° and ∠N = 60°, If ΔLMN ~ ΔPQR, then find ∠Q