CBSEClass 12MathsVector Algebra
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1. The position vector of the point (1, 0, 2) is

2. The modulus of 7\(\vec{i}\) – 2\(\vec{J}\) + \(\vec{K}\)

3. If O be the origin and \(\vec{OP}\) = 2\(\hat{i}\) + 3\(\hat{j}\) – 4\(\hat{k}\) and \(\vec{OQ}\) = 5\(\hat{i}\) + 4\(\hat{j}\) -3\(\hat{k}\), then \(\vec{PQ}\) is equal to

4. The scalar product of 5\(\hat{i}\) + \(\hat{j}\) – 3\(\hat{k}\) and 3\(\hat{i}\) – 4\(\hat{j}\) + 7\(\hat{k}\) is

5. If \(\vec{a}\).\(\vec{b}\) = 0, then

6. \(\vec{i}\) – \(\vec{j}\) =

7. \(\vec{k}\) × \(\vec{j}\) =

8. \(\vec{a}\). \(\vec{a}\) =

9. The projection of the vector 2\(\hat{i}\) – \(\hat{j}\) + \(\hat{k}\) on the vector \(\hat{i}\) – 2\(\hat{j}\) + \(\hat{k}\) is

10. If \(\vec{a}\) = \(\vec{i}\) – \(\vec{j}\) + 2\(\vec{k}\) and b = 3\(\vec{i}\) + 2\(\vec{j}\) – \(\vec{k}\) then the value of (\(\vec{a}\) + 3\(\vec{b}\))(2\(\vec{a}\) – \(\vec{b}\))=. (a) 15

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