4. The number of like terms in
abc, -abc, -bca, acb, bac, \(\frac{1}{2}\)cab is
5. The number of like terms in
\(\frac{1}{4}\)a²bc, - \(\frac{2}{3}\)bca², \(\frac{2}{5}\) ba²c, - \(\frac{1}{2}\)cba² is
7. If we add, 7xy + 5yz - 3zx, 4yz + 9zx - 4y and -3xz + 5x - 2xy, then the answer is: